Alford, R. and Pryor, N. (1992). Learning needs in industry: Meeting the challenge. In J. G. Hedberg and J. Steele (eds), Educational Technology for the Clever Country: Selected papers from EdTech'92, 39-48. Canberra: AJET Publications. http://www.aset.org.au/confs/edtech92/alford.html

Appendix C

Question as Presented

L.PGRM: PROT_1


Question: ( 2) (98/03/001)
--------------------------
A right-angled triangle has all 3 sides integers. If two of the sides 
are of length 12 and 13, what integer represents the third side?

 (a) Enter your numerical answer  [  ]

 (b) When performing your calculation, whose theorem did you use?
     Enter your answer [              ]
                   =========================================

Question as Marked

Question: ( 2) (98/03/001)

      7                             Incorrect - Correct Answer is 5
If 12 and 13 were taken to be the sides, the hypotenuse would not be an 
integer. Therefore the hypotenuse is 13. Use Pythagoras' Theorem.

      Pythageras                      Correct
You have been marked as correct, but the correct spelling is Pythagoras
                              Marks 1.0 out of 2.0

Question as Presented

Question 1.  ( 7) (98/07/006)
-----------------------------
In the circuit shown in the figure below, the two coils L1 and L2 are
mutually coupled with a coupling M = +j4 ohms and with polarity dots
shown at the top of each coil.
Find the voltage ratio V2/V1 which results in zero current I1.
Repeat for zero current I2. (Note the current directions, and V2/V1)



For zero current I1, ratio V2/V1 is:

     (a) Enter your answer for magnitude to 3 dec.pl.  [       ]
         ( You should be within 10% of 0.66 )

     (b) Enter your answer for angle to 1 dec.pl.      [       ]

For zero current I2, ration V2/V1 is:

     (c) Enter your answer for magnitude to 3 dec.pl.  [       ]

     (d) Enter your answer for magnitude to 3 dec.pl.  [       ]

Question as Marked

Question 1.  ( 7) (98/07/006)

(a) 0.111                           Incorrect - Correct Answer is 0.707
(b) -22.2                           Incorrect - Correct Answer is -45.0
(c) 0.333                           Incorrect - Correct Answer is 0.400
(d) 44.4                            Incorrect - Correct Answer is 36.9
The loop equations would be as follows:

     I1 (6 +j8)  +  I2 (+j4)    =  V1
     I1 (+j4)    +  I2 (2 +j2)  =  V1

It is only the numerator determinants that are of interest
                              Marks  0.0 out of 7.0